What are the solutions to the equation 0=3x^2+2x-8 ?

The solutions to the equation 0=3x^2+2x-8 are x= 4/3 ,x=-2

Find the zeros of 0=3x^2+2x-8

The zeros of 0=3x^2+2x-8 are x= 4/3 ,x=-2

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0 = 3 x^{2} + 2 x - 8

x = \frac{4}{3}, x = - 2

Solution steps

0 = 3 x^{2} + 2 x - 8

Switch sides

3 x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 10}{2 \cdot 3}

x = \frac{- 2 + 10}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 2 - 10}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 2

r^{2} - 6 r = 0

6 = x^{2}

x (x - 2) + 3 (x - 2) = 0

3 x^{2} + 8 x - 7 = 4

x, y + 3 x^{2} y = x^{2}

What are the solutions to the equation 0=3x^2+2x-8 ?
The solutions to the equation 0=3x^2+2x-8 are x= 4/3 ,x=-2
Find the zeros of 0=3x^2+2x-8
The zeros of 0=3x^2+2x-8 are x= 4/3 ,x=-2