What are the solutions to the equation 3d^2+24d+45=0 ?

The solutions to the equation 3d^2+24d+45=0 are d=-3,d=-5

Find the zeros of 3d^2+24d+45=0

The zeros of 3d^2+24d+45=0 are d=-3,d=-5

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3 d^{2} + 24 d + 45 = 0

d = - 3, d = - 5

Solution steps

3 d^{2} + 24 d + 45 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 45}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 45 = 6

d_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- 24 + 6}{2 \cdot 3}, d_{2} = \frac{- 24 - 6}{2 \cdot 3}

d = \frac{- 24 + 6}{2 \cdot 3} : - 3

d = \frac{- 24 - 6}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

d = - 3, d = - 5

x^{2} + (17 - x)^{2} = 169

y^{2} - y - 5 = 0

(3 x + 2) (2 x - 1) = 13

2 x^{2} + 11 x - 12 = 0

y^{2} = 1033

What are the solutions to the equation 3d^2+24d+45=0 ?
The solutions to the equation 3d^2+24d+45=0 are d=-3,d=-5
Find the zeros of 3d^2+24d+45=0
The zeros of 3d^2+24d+45=0 are d=-3,d=-5