What are the solutions to the equation 9x-8=x^2 ?

The solutions to the equation 9x-8=x^2 are x=8,x=1

Find the zeros of 9x-8=x^2

The zeros of 9x-8=x^2 are x=8,x=1

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9 x - 8 = x^{2}

x = 8, x = 1

Solution steps

9 x - 8 = x^{2}

Switch sides

x^{2} = 9 x - 8

Move

8

to the left side

x^{2} + 8 = 9 x

Move

9 x

to the left side

x^{2} + 8 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

x = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

x = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 8, x = 1

x, y^{3} + 3 y^{2} - 9 y = x^{2} + 10 x + 12

x^{2} - 23 x + 44 = - 5 x + 5

2 x^{2} = - 200

2 p^{2} + 5 p - 4 = 0

x (x - 9) = 10

What are the solutions to the equation 9x-8=x^2 ?
The solutions to the equation 9x-8=x^2 are x=8,x=1
Find the zeros of 9x-8=x^2
The zeros of 9x-8=x^2 are x=8,x=1