What are the solutions to the equation x^2-23x+44=-5x+5 ?

The solutions to the equation x^2-23x+44=-5x+5 are x=9+sqrt(42),x=9-sqrt(42)

Find the zeros of x^2-23x+44=-5x+5

The zeros of x^2-23x+44=-5x+5 are x=9+sqrt(42),x=9-sqrt(42)

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x^{2} - 23 x + 44 = - 5 x + 5

x = 9 + 42, x = 9 - 42

Solution steps

x^{2} - 23 x + 44 = - 5 x + 5

Move

5

to the left side

x^{2} - 23 x + 39 = - 5 x

Move

5 x

to the left side

x^{2} - 18 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 39}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 39 = 242

x_{1, 2} = \frac{- ( - 18 ) \pm 2 42}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 42}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 42}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 42}{2 \cdot 1} : 9 + 42

x = \frac{- ( - 18 ) - 2 42}{2 \cdot 1} : 9 - 42

The solutions to the quadratic equation are:

x = 9 + 42, x = 9 - 42

2 x^{2} = - 200

2 p^{2} + 5 p - 4 = 0

x (x - 9) = 10

x, x^{2} + y^{2} + 8 x - 2 y + 17 = 0

81 x^{2} - 4 = 0

What are the solutions to the equation x^2-23x+44=-5x+5 ?
The solutions to the equation x^2-23x+44=-5x+5 are x=9+sqrt(42),x=9-sqrt(42)
Find the zeros of x^2-23x+44=-5x+5
The zeros of x^2-23x+44=-5x+5 are x=9+sqrt(42),x=9-sqrt(42)