What are the solutions to the equation 2p^2+5p-4=0 ?

The solutions to the equation 2p^2+5p-4=0 are p=(-5+sqrt(57))/4 ,p=(-5-sqrt(57))/4

Find the zeros of 2p^2+5p-4=0

The zeros of 2p^2+5p-4=0 are p=(-5+sqrt(57))/4 ,p=(-5-sqrt(57))/4

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2 p^{2} + 5 p - 4 = 0

p = \frac{- 5 + 57}{4}, p = \frac{- 5 - 57}{4}

Solution steps

2 p^{2} + 5 p - 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 4) = 57

p_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 5 + 57}{2 \cdot 2}, p_{2} = \frac{- 5 - 57}{2 \cdot 2}

p = \frac{- 5 + 57}{2 \cdot 2} : \frac{- 5 + 57}{4}

p = \frac{- 5 - 57}{2 \cdot 2} : \frac{- 5 - 57}{4}

The solutions to the quadratic equation are:

p = \frac{- 5 + 57}{4}, p = \frac{- 5 - 57}{4}

x (x - 9) = 10

x, x^{2} + y^{2} + 8 x - 2 y + 17 = 0

81 x^{2} - 4 = 0

- 2 x - 5 = x^{2} - 7 x - 55

3 x^{2} - x = 0

What are the solutions to the equation 2p^2+5p-4=0 ?
The solutions to the equation 2p^2+5p-4=0 are p=(-5+sqrt(57))/4 ,p=(-5-sqrt(57))/4
Find the zeros of 2p^2+5p-4=0
The zeros of 2p^2+5p-4=0 are p=(-5+sqrt(57))/4 ,p=(-5-sqrt(57))/4