What are the solutions to the equation 81x^2-4=0 ?

The solutions to the equation 81x^2-4=0 are x= 2/9 ,x=-2/9

Find the zeros of 81x^2-4=0

The zeros of 81x^2-4=0 are x= 2/9 ,x=-2/9

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81 x^{2} - 4 = 0

x = \frac{2}{9}, x = - \frac{2}{9}

Solution steps

81 x^{2} - 4 = 0

Move

4

to the right side

81 x^{2} = 4

Divide both sides by

81

x^{2} = \frac{4}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{81}, x = - \frac{4}{81}

\frac{4}{81} = \frac{2}{9}

- \frac{4}{81} = - \frac{2}{9}

x = \frac{2}{9}, x = - \frac{2}{9}

- 2 x - 5 = x^{2} - 7 x - 55

3 x^{2} - x = 0

5 x^{2} + 145 = - 60 x

(x - 3)^{2} + x^{2} = (x + 4) (x - 2) + 2

- x \times (- x - 2) - (x - \frac{1}{2}) \times 2 x + 8 = x^{2} - 1

What are the solutions to the equation 81x^2-4=0 ?
The solutions to the equation 81x^2-4=0 are x= 2/9 ,x=-2/9
Find the zeros of 81x^2-4=0
The zeros of 81x^2-4=0 are x= 2/9 ,x=-2/9