What are the solutions to the equation 5x^2+145=-60x ?

The solutions to the equation 5x^2+145=-60x are x=-6+sqrt(7),x=-6-sqrt(7)

Find the zeros of 5x^2+145=-60x

The zeros of 5x^2+145=-60x are x=-6+sqrt(7),x=-6-sqrt(7)

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5 x^{2} + 145 = - 60 x

x = - 6 + 7, x = - 6 - 7

Solution steps

5 x^{2} + 145 = - 60 x

Move

60 x

to the left side

5 x^{2} + 145 + 60 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} + 60 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 5 \cdot 145}{2 \cdot 5}

6 0^{2} - 4 \cdot 5 \cdot 145 = 107

x_{1, 2} = \frac{- 60 \pm 10 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 60 + 10 7}{2 \cdot 5}, x_{2} = \frac{- 60 - 10 7}{2 \cdot 5}

x = \frac{- 60 + 10 7}{2 \cdot 5} : - 6 + 7

x = \frac{- 60 - 10 7}{2 \cdot 5} : - 6 - 7

The solutions to the quadratic equation are:

x = - 6 + 7, x = - 6 - 7

(x - 3)^{2} + x^{2} = (x + 4) (x - 2) + 2

- x \times (- x - 2) - (x - \frac{1}{2}) \times 2 x + 8 = x^{2} - 1

x^{2} + 8 x = - 9

4 x^{2} - 5 x - 5 = 0

\frac{1}{5} q^{2} + 10 = 86 - 6 q - 3 q^{2}

What are the solutions to the equation 5x^2+145=-60x ?
The solutions to the equation 5x^2+145=-60x are x=-6+sqrt(7),x=-6-sqrt(7)
Find the zeros of 5x^2+145=-60x
The zeros of 5x^2+145=-60x are x=-6+sqrt(7),x=-6-sqrt(7)