What are the solutions to the equation x^2+ax=0 ?

The solutions to the equation x^2+ax=0 are x=0,x=-a

Find the zeros of x^2+ax=0

The zeros of x^2+ax=0 are x=0,x=-a

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x^{2} + a x = 0

x = 0, x = - a

Solution steps

x^{2} + a x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

a^{2} - 4 \cdot 1 \cdot 0 : a

x_{1, 2} = \frac{- a \pm a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- a + a}{2 \cdot 1}, x_{2} = \frac{- a - a}{2 \cdot 1}

x = \frac{- a + a}{2 \cdot 1} : 0

x = \frac{- a - a}{2 \cdot 1} : - a

The solutions to the quadratic equation are:

x = 0, x = - a

x^{2} + x + 13 = 0

s^{2} + 6 s + 10

- 0.004 x^{2} + 250 = 0.0024 x^{2} + 0.04 x + 100

s^{2} + 6 s + 34

(x^{2} - 5 x + 9) \cdot lo g_{10} (2) + lo g_{10} (125) = 3

What are the solutions to the equation x^2+ax=0 ?
The solutions to the equation x^2+ax=0 are x=0,x=-a
Find the zeros of x^2+ax=0
The zeros of x^2+ax=0 are x=0,x=-a