What are the solutions to the equation -x^2-14x+21=-2x+7 ?

The solutions to the equation -x^2-14x+21=-2x+7 are x=-6-5sqrt(2),x=5sqrt(2)-6

Find the zeros of -x^2-14x+21=-2x+7

The zeros of -x^2-14x+21=-2x+7 are x=-6-5sqrt(2),x=5sqrt(2)-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} - 14 x + 21 = - 2 x + 7

x = - 6 - 52, x = 52 - 6

Decimal Notation

x = - 13.07106 \dots, x = 1.07106 \dots

Solution steps

- x^{2} - 14 x + 21 = - 2 x + 7

Move

7

to the left side

- x^{2} - 14 x + 14 = - 2 x

Move

2 x

to the left side

- x^{2} - 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) \cdot 14}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) \cdot 14 = 102

x_{1, 2} = \frac{- ( - 12 ) \pm 10 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 12 ) - 10 2}{2 ( - 1 )}

x = \frac{- ( - 12 ) + 10 2}{2 ( - 1 )} : - 6 - 52

x = \frac{- ( - 12 ) - 10 2}{2 ( - 1 )} : 52 - 6

The solutions to the quadratic equation are:

x = - 6 - 52, x = 52 - 6

(3 x + 4)^{2} = 0

x, (x + y)^{2} y = 9

x^{2} + 2 = 3 x^{2} - 16

3 x (x - 2) = 2 (x - 2)

3 x^{2} + 6 x = 0

What are the solutions to the equation -x^2-14x+21=-2x+7 ?
The solutions to the equation -x^2-14x+21=-2x+7 are x=-6-5sqrt(2),x=5sqrt(2)-6
Find the zeros of -x^2-14x+21=-2x+7
The zeros of -x^2-14x+21=-2x+7 are x=-6-5sqrt(2),x=5sqrt(2)-6