What are the solutions to the equation factor 2x^2-5x+2=0 ?

The solutions to the equation factor 2x^2-5x+2=0 are x= 1/2 ,x=2

Find the zeros of factor 2x^2-5x+2=0

The zeros of factor 2x^2-5x+2=0 are x= 1/2 ,x=2

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2 x^{2} - 5 x + 2 = 0

x = \frac{1}{2}, x = 2

Decimal Notation

x = 0.5, x = 2

Solution steps

2 x^{2} - 5 x + 2 = 0

Factor

2 x^{2} - 5 x + 2 : (2 x - 1) (x - 2)

(2 x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x - 2 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 2

x^{2} - \frac{1}{2} x - 3 = 0

\frac{4}{9} - \frac{d ^{2}}{25} = 0

s^{2} = - 1

x, 9 x^{2} + 12 x y + 4 y^{2} - 48 x - 32 y + 64 = 0

x^{2} - 8 = - 2 x

What are the solutions to the equation factor 2x^2-5x+2=0 ?
The solutions to the equation factor 2x^2-5x+2=0 are x= 1/2 ,x=2
Find the zeros of factor 2x^2-5x+2=0
The zeros of factor 2x^2-5x+2=0 are x= 1/2 ,x=2