What are the solutions to the equation -3x^2+4x+59=-8x-4 ?

The solutions to the equation -3x^2+4x+59=-8x-4 are x=-3,x=7

Find the zeros of -3x^2+4x+59=-8x-4

The zeros of -3x^2+4x+59=-8x-4 are x=-3,x=7

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- 3 x^{2} + 4 x + 59 = - 8 x - 4

x = - 3, x = 7

Solution steps

- 3 x^{2} + 4 x + 59 = - 8 x - 4

Move

4

to the left side

- 3 x^{2} + 4 x + 63 = - 8 x

Move

8 x

to the left side

- 3 x^{2} + 12 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) \cdot 63}{2 ( - 3 )}

1 2^{2} - 4 (- 3) \cdot 63 = 30

x_{1, 2} = \frac{- 12 \pm 30}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 30}{2 ( - 3 )}, x_{2} = \frac{- 12 - 30}{2 ( - 3 )}

x = \frac{- 12 + 30}{2 ( - 3 )} : - 3

x = \frac{- 12 - 30}{2 ( - 3 )} : 7

The solutions to the quadratic equation are:

x = - 3, x = 7

(x - 5) (40 - x) = 4 (40 - x)

2 x + x^{2} = 4

x^{2} - 12 x + 36

x, x^{2} + y^{2} - 6 x - 6 y + 18 = 0

(2 x - 3) (5 x - 1) = x^{2} + 5

What are the solutions to the equation -3x^2+4x+59=-8x-4 ?
The solutions to the equation -3x^2+4x+59=-8x-4 are x=-3,x=7
Find the zeros of -3x^2+4x+59=-8x-4
The zeros of -3x^2+4x+59=-8x-4 are x=-3,x=7