What are the solutions to the equation (x-5)(40-x)=4(40-x) ?

The solutions to the equation (x-5)(40-x)=4(40-x) are x=9,x=40

Find the zeros of (x-5)(40-x)=4(40-x)

The zeros of (x-5)(40-x)=4(40-x) are x=9,x=40

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(x - 5) (40 - x) = 4 (40 - x)

x = 9, x = 40

Solution steps

(x - 5) (40 - x) = 4 (40 - x)

Move

4 (40 - x)

to the left side

(x - 5) (40 - x) - 4 (40 - x) = 0

Factor

(x - 5) (40 - x) - 4 (40 - x) : - (x - 9) (x - 40)

- (x - 9) (x - 40) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x - 40 = 0

Solve

x - 9 = 0 : x = 9

Solve

x - 40 = 0 : x = 40

The solutions to the quadratic equation are:

x = 9, x = 40

2 x + x^{2} = 4

x^{2} - 12 x + 36

x, x^{2} + y^{2} - 6 x - 6 y + 18 = 0

(2 x - 3) (5 x - 1) = x^{2} + 5

w^{2} - 5 w - \frac{11}{4} = 0

What are the solutions to the equation (x-5)(40-x)=4(40-x) ?
The solutions to the equation (x-5)(40-x)=4(40-x) are x=9,x=40
Find the zeros of (x-5)(40-x)=4(40-x)
The zeros of (x-5)(40-x)=4(40-x) are x=9,x=40