What are the solutions to the equation w^2-5w-11/4 =0 ?

The solutions to the equation w^2-5w-11/4 =0 are w= 11/2 ,w=-1/2

Find the zeros of w^2-5w-11/4 =0

The zeros of w^2-5w-11/4 =0 are w= 11/2 ,w=-1/2

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w^{2} - 5 w - \frac{11}{4} = 0

w = \frac{11}{2}, w = - \frac{1}{2}

Solution steps

w^{2} - 5 w - \frac{11}{4} = 0

Multiply both sides by

4

4 w^{2} - 20 w - 11 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 ( - 11 )}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 (- 11) = 24

w_{1, 2} = \frac{- ( - 20 ) \pm 24}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 20 ) + 24}{2 \cdot 4}, w_{2} = \frac{- ( - 20 ) - 24}{2 \cdot 4}

w = \frac{- ( - 20 ) + 24}{2 \cdot 4} : \frac{11}{2}

w = \frac{- ( - 20 ) - 24}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

w = \frac{11}{2}, w = - \frac{1}{2}

4 x^{2} + 16 x + 4 = 0

(x + 6) (x + 3) = 4

3 p^{2} + 5 p = 68

n^{2} - 4 n + 3 = 0

2 x + 2 = x^{2} + 4 x + 3

What are the solutions to the equation w^2-5w-11/4 =0 ?
The solutions to the equation w^2-5w-11/4 =0 are w= 11/2 ,w=-1/2
Find the zeros of w^2-5w-11/4 =0
The zeros of w^2-5w-11/4 =0 are w= 11/2 ,w=-1/2