What are the solutions to the equation (x+6)(x+3)=4 ?

The solutions to the equation (x+6)(x+3)=4 are x=-2,x=-7

Find the zeros of (x+6)(x+3)=4

The zeros of (x+6)(x+3)=4 are x=-2,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 6) (x + 3) = 4

x = - 2, x = - 7

Solution steps

(x + 6) (x + 3) = 4

Expand

(x + 6) (x + 3) : x^{2} + 9 x + 18

x^{2} + 9 x + 18 = 4

Move

4

to the left side

x^{2} + 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 \cdot 1}, x_{2} = \frac{- 9 - 5}{2 \cdot 1}

x = \frac{- 9 + 5}{2 \cdot 1} : - 2

x = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 2, x = - 7

3 p^{2} + 5 p = 68

n^{2} - 4 n + 3 = 0

2 x + 2 = x^{2} + 4 x + 3

2 x^{2} + 16 x - 20 = 0

x, 4 x^{2} + 2 x y + y^{2} = 0

What are the solutions to the equation (x+6)(x+3)=4 ?
The solutions to the equation (x+6)(x+3)=4 are x=-2,x=-7
Find the zeros of (x+6)(x+3)=4
The zeros of (x+6)(x+3)=4 are x=-2,x=-7