What are the solutions to the equation 2x+2=x^2+4x+3 ?

The solutions to the equation 2x+2=x^2+4x+3 are x=-1

Find the zeros of 2x+2=x^2+4x+3

The zeros of 2x+2=x^2+4x+3 are x=-1

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2 x + 2 = x^{2} + 4 x + 3

x = - 1

Solution steps

2 x + 2 = x^{2} + 4 x + 3

Switch sides

x^{2} + 4 x + 3 = 2 x + 2

Move

2

to the left side

x^{2} + 4 x + 1 = 2 x

Move

2 x

to the left side

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

2 x^{2} + 16 x - 20 = 0

x, 4 x^{2} + 2 x y + y^{2} = 0

2 w^{2} + 11 w - 63 = 0

1 + 0.2 x - 0.48 x^{2} = 0

x, \frac{1}{2} + \frac{x ^{2}}{32} = R

What are the solutions to the equation 2x+2=x^2+4x+3 ?
The solutions to the equation 2x+2=x^2+4x+3 are x=-1
Find the zeros of 2x+2=x^2+4x+3
The zeros of 2x+2=x^2+4x+3 are x=-1