What are the solutions to the equation x^2-3+2x=0 ?

The solutions to the equation x^2-3+2x=0 are x=1,x=-3

Find the zeros of x^2-3+2x=0

The zeros of x^2-3+2x=0 are x=1,x=-3

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x^{2} - 3 + 2 x = 0

x = 1, x = - 3

Solution steps

x^{2} - 3 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

y, x^{3} - 2 x^{2} y + 3 x y^{2} = 38

2 4^{2} + b^{2} = 2 6^{2}

r, v = πh r^{2}

1600 (x + 2) + 1600 x = 360 x (x + 2)

What are the solutions to the equation x^2-3+2x=0 ?
The solutions to the equation x^2-3+2x=0 are x=1,x=-3
Find the zeros of x^2-3+2x=0
The zeros of x^2-3+2x=0 are x=1,x=-3