What are the solutions to the equation 2x^2-3x(20)+50(20)^2=28000 ?

The solutions to the equation 2x^2-3x(20)+50(20)^2=28000 are x=80,x=-50

Find the zeros of 2x^2-3x(20)+50(20)^2=28000

The zeros of 2x^2-3x(20)+50(20)^2=28000 are x=80,x=-50

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2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

x = 80, x = - 50

Solution steps

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

Expand

2 x^{2} - 3 x (20) + 50 \cdot 2 0^{2} : 2 x^{2} - 60 x + 20000

2 x^{2} - 60 x + 20000 = 28000

Move

28000

to the left side

2 x^{2} - 60 x - 8000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 2 ( - 8000 )}{2 \cdot 2}

(- 60)^{2} - 4 \cdot 2 (- 8000) = 260

x_{1, 2} = \frac{- ( - 60 ) \pm 260}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 260}{2 \cdot 2}, x_{2} = \frac{- ( - 60 ) - 260}{2 \cdot 2}

x = \frac{- ( - 60 ) + 260}{2 \cdot 2} : 80

x = \frac{- ( - 60 ) - 260}{2 \cdot 2} : - 50

The solutions to the quadratic equation are:

x = 80, x = - 50

y, x^{3} - 2 x^{2} y + 3 x y^{2} = 38

2 4^{2} + b^{2} = 2 6^{2}

r, v = πh r^{2}

1600 (x + 2) + 1600 x = 360 x (x + 2)

\frac{- 3 x ^{2} + 1200}{4} = 0

What are the solutions to the equation 2x^2-3x(20)+50(20)^2=28000 ?
The solutions to the equation 2x^2-3x(20)+50(20)^2=28000 are x=80,x=-50
Find the zeros of 2x^2-3x(20)+50(20)^2=28000
The zeros of 2x^2-3x(20)+50(20)^2=28000 are x=80,x=-50