What are the solutions to the equation (-3x^2+1200)/4 =0 ?

The solutions to the equation (-3x^2+1200)/4 =0 are x=20,x=-20

Find the zeros of (-3x^2+1200)/4 =0

The zeros of (-3x^2+1200)/4 =0 are x=20,x=-20

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\frac{- 3 x ^{2} + 1200}{4} = 0

x = 20, x = - 20

Solution steps

\frac{- 3 x ^{2} + 1200}{4} = 0

Multiply both sides by

4

- 3 x^{2} + 1200 = 0

Move

1200

to the right side

- 3 x^{2} = - 1200

Divide both sides by

- 3

x^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 400, x = - 400

400 = 20

- 400 = - 20

x = 20, x = - 20

w^{2} - 11 w + 28 = 0

- 9 n^{2} + 6 = - 30

3 x^{2} - 2 x - 17 = - 1

(z - 6)^{2} = 2 z

5 x^{2} + 13 x - 46 = 0

What are the solutions to the equation (-3x^2+1200)/4 =0 ?
The solutions to the equation (-3x^2+1200)/4 =0 are x=20,x=-20
Find the zeros of (-3x^2+1200)/4 =0
The zeros of (-3x^2+1200)/4 =0 are x=20,x=-20