What are the solutions to the equation 0=x^{(2)}+2x-15 ?

The solutions to the equation 0=x^{(2)}+2x-15 are x=3,x=-5

Find the zeros of 0=x^{(2)}+2x-15

The zeros of 0=x^{(2)}+2x-15 are x=3,x=-5

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0 = x^{(2)} + 2 x - 15

x = 3, x = - 5

Solution steps

0 = x^{(2)} + 2 x - 15

Refine

0 = x^{2} + 2 x - 15

Switch sides

x^{2} + 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 1}, x_{2} = \frac{- 2 - 8}{2 \cdot 1}

x = \frac{- 2 + 8}{2 \cdot 1} : 3

x = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

x, z^{2} = x^{2} + x y^{2} z

4 w^{2} + 25 = - 20 w

0 = 3 x^{2} + 10 x - 8

(x + 5)^{2} = - 16

(6.4 \cdot 1 0^{- 7} - x) (11.4 \cdot 1 0^{- 7} - x) = 4.1 \cdot 1 0^{- 13}

What are the solutions to the equation 0=x^{(2)}+2x-15 ?
The solutions to the equation 0=x^{(2)}+2x-15 are x=3,x=-5
Find the zeros of 0=x^{(2)}+2x-15
The zeros of 0=x^{(2)}+2x-15 are x=3,x=-5