What are the solutions to the equation 2n^2+5n+2=0 ?

The solutions to the equation 2n^2+5n+2=0 are n=-1/2 ,n=-2

Find the zeros of 2n^2+5n+2=0

The zeros of 2n^2+5n+2=0 are n=-1/2 ,n=-2

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2 n^{2} + 5 n + 2 = 0

n = - \frac{1}{2}, n = - 2

Decimal Notation

n = - 0.5, n = - 2

Solution steps

2 n^{2} + 5 n + 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

n_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 5 + 3}{2 \cdot 2}, n_{2} = \frac{- 5 - 3}{2 \cdot 2}

n = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

n = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

n = - \frac{1}{2}, n = - 2

x (x + 10) + 20 = - 5

10 x^{2} - 60 x = 0

6 x^{2} - 13 x = 5

x, 9 x^{2} - 4 y^{2} = 0

c, y^{2} (x) = c (x + \frac{c}{4})

What are the solutions to the equation 2n^2+5n+2=0 ?
The solutions to the equation 2n^2+5n+2=0 are n=-1/2 ,n=-2
Find the zeros of 2n^2+5n+2=0
The zeros of 2n^2+5n+2=0 are n=-1/2 ,n=-2