What are the solutions to the equation x^2-20x+118=0 ?

The solutions to the equation x^2-20x+118=0 are x=10+3sqrt(2)i,x=10-3sqrt(2)i

Find the zeros of x^2-20x+118=0

The zeros of x^2-20x+118=0 are x=10+3sqrt(2)i,x=10-3sqrt(2)i

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x^{2} - 20 x + 118 = 0

x = 10 + 32 i, x = 10 - 32 i

Solution steps

x^{2} - 20 x + 118 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 118}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot 118 : 62 i

x_{1, 2} = \frac{- ( - 20 ) \pm 6 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 6 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 6 2 i}{2 \cdot 1}

x = \frac{- ( - 20 ) + 6 2 i}{2 \cdot 1} : 10 + 32 i

x = \frac{- ( - 20 ) - 6 2 i}{2 \cdot 1} : 10 - 32 i

The solutions to the quadratic equation are:

x = 10 + 32 i, x = 10 - 32 i

(x^{2} + 16) = 0

(6 x) (x - 6) = 0

- x^{2} - 10 x = 0

45 x^{2} - 78 x - 63 = 0

4 - 4 x^{2} = - 296

What are the solutions to the equation x^2-20x+118=0 ?
The solutions to the equation x^2-20x+118=0 are x=10+3sqrt(2)i,x=10-3sqrt(2)i
Find the zeros of x^2-20x+118=0
The zeros of x^2-20x+118=0 are x=10+3sqrt(2)i,x=10-3sqrt(2)i