What are the solutions to the equation 5x^2+4x+9=0 ?

The solutions to the equation 5x^2+4x+9=0 are x=-2/5+i(sqrt(41))/5 ,x=-2/5-i(sqrt(41))/5

Find the zeros of 5x^2+4x+9=0

The zeros of 5x^2+4x+9=0 are x=-2/5+i(sqrt(41))/5 ,x=-2/5-i(sqrt(41))/5

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5 x^{2} + 4 x + 9 = 0

x = - \frac{2}{5} + i \frac{41}{5}, x = - \frac{2}{5} - i \frac{41}{5}

Solution steps

5 x^{2} + 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 9}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 9 : 241 i

x_{1, 2} = \frac{- 4 \pm 2 41 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 41 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 41 i}{2 \cdot 5}

x = \frac{- 4 + 2 41 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{41}{5}

x = \frac{- 4 - 2 41 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{41}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{41}{5}, x = - \frac{2}{5} - i \frac{41}{5}

2 x^{2} - x = - 8

(7 - 3 x) (x + 2) = 4

x^{2} - 6 x - 7 = 0

15000 = - 0.5 x^{2} + 40 x - 300

\frac{x ^{2}}{3} = \frac{11}{6} x + 1

What are the solutions to the equation 5x^2+4x+9=0 ?
The solutions to the equation 5x^2+4x+9=0 are x=-2/5+i(sqrt(41))/5 ,x=-2/5-i(sqrt(41))/5
Find the zeros of 5x^2+4x+9=0
The zeros of 5x^2+4x+9=0 are x=-2/5+i(sqrt(41))/5 ,x=-2/5-i(sqrt(41))/5