What are the solutions to the equation solvefor x,x^2+2ax+a^2-n=0 ?

The solutions to the equation solvefor x,x^2+2ax+a^2-n=0 are x=-a+sqrt(n),x=-a-sqrt(n)

Find the zeros of solvefor x,x^2+2ax+a^2-n=0

The zeros of solvefor x,x^2+2ax+a^2-n=0 are x=-a+sqrt(n),x=-a-sqrt(n)

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x, x^{2} + 2 a x + a^{2} - n = 0

x = - a + n, x = - a - n

Solution steps

x^{2} + 2 a x + a^{2} - n = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 a \pm ( 2 a ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} - n )}{2 \cdot 1}

Simplify

(2 a)^{2} - 4 \cdot 1 \cdot (a^{2} - n) : 2 n

x_{1, 2} = \frac{- 2 a \pm 2 n}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 a + 2 n}{2 \cdot 1}, x_{2} = \frac{- 2 a - 2 n}{2 \cdot 1}

x = \frac{- 2 a + 2 n}{2 \cdot 1} : - a + n

x = \frac{- 2 a - 2 n}{2 \cdot 1} : - a - n

The solutions to the quadratic equation are:

x = - a + n, x = - a - n

x^{2} + 2 x + 65 = 0

x^{2} - 10 x = - 11

x^{2} - 10 x = - 13

x^{2} - 10 x = - 15

x, 2 x^{2} - 5 x + 2 = 0

What are the solutions to the equation solvefor x,x^2+2ax+a^2-n=0 ?
The solutions to the equation solvefor x,x^2+2ax+a^2-n=0 are x=-a+sqrt(n),x=-a-sqrt(n)
Find the zeros of solvefor x,x^2+2ax+a^2-n=0
The zeros of solvefor x,x^2+2ax+a^2-n=0 are x=-a+sqrt(n),x=-a-sqrt(n)