What are the solutions to the equation x^2-10x=-13 ?

The solutions to the equation x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)

Find the zeros of x^2-10x=-13

The zeros of x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)

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x^{2} - 10 x = - 13

x = 5 + 23, x = 5 - 23

Decimal Notation

x = 8.46410 \dots, x = 1.53589 \dots

Solution steps

x^{2} - 10 x = - 13

Move

13

to the left side

x^{2} - 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 13 = 43

x_{1, 2} = \frac{- ( - 10 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 3}{2 \cdot 1} : 5 + 23

x = \frac{- ( - 10 ) - 4 3}{2 \cdot 1} : 5 - 23

The solutions to the quadratic equation are:

x = 5 + 23, x = 5 - 23

x^{2} - 10 x = - 15

x, 2 x^{2} - 5 x + 2 = 0

- 5 x^{2} + 5 x - 1.2 = 0

- 5 x^{2} - 6 = - 4 x

6 t^{2} - 13 t = 15

What are the solutions to the equation x^2-10x=-13 ?
The solutions to the equation x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)
Find the zeros of x^2-10x=-13
The zeros of x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)