What are the solutions to the equation 20x^2-5x-12=0 ?

The solutions to the equation 20x^2-5x-12=0 are x=(5+sqrt(985))/(40),x=(5-sqrt(985))/(40)

Find the zeros of 20x^2-5x-12=0

The zeros of 20x^2-5x-12=0 are x=(5+sqrt(985))/(40),x=(5-sqrt(985))/(40)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

20 x^{2} - 5 x - 12 = 0

x = \frac{5 + 985}{40}, x = \frac{5 - 985}{40}

Decimal Notation

x = 0.90961 \dots, x = - 0.65961 \dots

Solution steps

20 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 20 ( - 12 )}{2 \cdot 20}

(- 5)^{2} - 4 \cdot 20 (- 12) = 985

x_{1, 2} = \frac{- ( - 5 ) \pm 985}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 985}{2 \cdot 20}, x_{2} = \frac{- ( - 5 ) - 985}{2 \cdot 20}

x = \frac{- ( - 5 ) + 985}{2 \cdot 20} : \frac{5 + 985}{40}

x = \frac{- ( - 5 ) - 985}{2 \cdot 20} : \frac{5 - 985}{40}

The solutions to the quadratic equation are:

x = \frac{5 + 985}{40}, x = \frac{5 - 985}{40}

x^{2} + 12 x - 8 = 0

- 4 x^{2} - 6 x + 1 = 0

(5 x - 9)^{2} = 1296

- 5 x^{2} - 87 x - 391 = 3 x - 63 x - 6

x, x^{2} + y^{2} - 4 x + 10 y + 29 = 0

What are the solutions to the equation 20x^2-5x-12=0 ?
The solutions to the equation 20x^2-5x-12=0 are x=(5+sqrt(985))/(40),x=(5-sqrt(985))/(40)
Find the zeros of 20x^2-5x-12=0
The zeros of 20x^2-5x-12=0 are x=(5+sqrt(985))/(40),x=(5-sqrt(985))/(40)