What are the solutions to the equation -4x^2+x-9=0 ?

The solutions to the equation -4x^2+x-9=0 are x= 1/8-i(sqrt(143))/8 ,x= 1/8+i(sqrt(143))/8

Find the zeros of -4x^2+x-9=0

The zeros of -4x^2+x-9=0 are x= 1/8-i(sqrt(143))/8 ,x= 1/8+i(sqrt(143))/8

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- 4 x^{2} + x - 9 = 0

x = \frac{1}{8} - i \frac{143}{8}, x = \frac{1}{8} + i \frac{143}{8}

Solution steps

- 4 x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

Simplify

1^{2} - 4 (- 4) (- 9) : 143 i

x_{1, 2} = \frac{- 1 \pm 143 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 143 i}{2 ( - 4 )}, x_{2} = \frac{- 1 - 143 i}{2 ( - 4 )}

x = \frac{- 1 + 143 i}{2 ( - 4 )} : \frac{1}{8} - i \frac{143}{8}

x = \frac{- 1 - 143 i}{2 ( - 4 )} : \frac{1}{8} + i \frac{143}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} - i \frac{143}{8}, x = \frac{1}{8} + i \frac{143}{8}

m^{2} = 144

(x - 3)^{2} + (- 3)^{2} = 0.5

3 x^{2} - 6 x = - 1

\frac{x ^{2}}{36} + \frac{( x + 4 ) ^{2}}{64} = 1

4 x^{2} + 32 x = - 16

What are the solutions to the equation -4x^2+x-9=0 ?
The solutions to the equation -4x^2+x-9=0 are x= 1/8-i(sqrt(143))/8 ,x= 1/8+i(sqrt(143))/8
Find the zeros of -4x^2+x-9=0
The zeros of -4x^2+x-9=0 are x= 1/8-i(sqrt(143))/8 ,x= 1/8+i(sqrt(143))/8