What are the solutions to the equation (x-3)^2+(-3)^2=0.5 ?

The solutions to the equation (x-3)^2+(-3)^2=0.5 are x=2.91547…i+3,x=-2.91547…i+3

Find the zeros of (x-3)^2+(-3)^2=0.5

The zeros of (x-3)^2+(-3)^2=0.5 are x=2.91547…i+3,x=-2.91547…i+3

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(x - 3)^{2} + (- 3)^{2} = 0.5

x = 2.91547 \dots i + 3, x = - 2.91547 \dots i + 3

Solution steps

(x - 3)^{2} + (- 3)^{2} = 0.5

Move

(- 3)^{2}

to the right side

(x - 3)^{2} = - 8.5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 8.5 : x = 2.91547 \dots i + 3

Solve

x - 3 = - - 8.5 : x = - 2.91547 \dots i + 3

The solutions to the quadratic equation are:

x = 2.91547 \dots i + 3, x = - 2.91547 \dots i + 3

3 x^{2} - 6 x = - 1

\frac{x ^{2}}{36} + \frac{( x + 4 ) ^{2}}{64} = 1

4 x^{2} + 32 x = - 16

2 x^{2} = - 12 x - 18

- 4 x^{2} + 88 x = 0

What are the solutions to the equation (x-3)^2+(-3)^2=0.5 ?
The solutions to the equation (x-3)^2+(-3)^2=0.5 are x=2.91547…i+3,x=-2.91547…i+3
Find the zeros of (x-3)^2+(-3)^2=0.5
The zeros of (x-3)^2+(-3)^2=0.5 are x=2.91547…i+3,x=-2.91547…i+3