What are the solutions to the equation 3a^2+2a=7 ?

The solutions to the equation 3a^2+2a=7 are a=(-1+sqrt(22))/3 ,a=-(1+sqrt(22))/3

Find the zeros of 3a^2+2a=7

The zeros of 3a^2+2a=7 are a=(-1+sqrt(22))/3 ,a=-(1+sqrt(22))/3

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3 a^{2} + 2 a = 7

a = \frac{- 1 + 22}{3}, a = - \frac{1 + 22}{3}

Decimal Notation

a = 1.23013 \dots, a = - 1.89680 \dots

Solution steps

3 a^{2} + 2 a = 7

Move

7

to the left side

3 a^{2} + 2 a - 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 7) = 222

a_{1, 2} = \frac{- 2 \pm 2 22}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 2 + 2 22}{2 \cdot 3}, a_{2} = \frac{- 2 - 2 22}{2 \cdot 3}

a = \frac{- 2 + 2 22}{2 \cdot 3} : \frac{- 1 + 22}{3}

a = \frac{- 2 - 2 22}{2 \cdot 3} : - \frac{1 + 22}{3}

The solutions to the quadratic equation are:

a = \frac{- 1 + 22}{3}, a = - \frac{1 + 22}{3}

x + x^{2} = 12

x^{2} - 16 x - 84 = - 5

7 x^{2} + 21 x - 28 = 0

2 = 2 x^{2}

x - 6 = - x^{2} - 14 x - 60

What are the solutions to the equation 3a^2+2a=7 ?
The solutions to the equation 3a^2+2a=7 are a=(-1+sqrt(22))/3 ,a=-(1+sqrt(22))/3
Find the zeros of 3a^2+2a=7
The zeros of 3a^2+2a=7 are a=(-1+sqrt(22))/3 ,a=-(1+sqrt(22))/3