What are the solutions to the equation x^2-16x-84=-5 ?

The solutions to the equation x^2-16x-84=-5 are x=8+sqrt(143),x=8-sqrt(143)

Find the zeros of x^2-16x-84=-5

The zeros of x^2-16x-84=-5 are x=8+sqrt(143),x=8-sqrt(143)

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x^{2} - 16 x - 84 = - 5

x = 8 + 143, x = 8 - 143

Decimal Notation

x = 19.95826 \dots, x = - 3.95826 \dots

Solution steps

x^{2} - 16 x - 84 = - 5

Move

5

to the left side

x^{2} - 16 x - 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 79 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 79) = 2143

x_{1, 2} = \frac{- ( - 16 ) \pm 2 143}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 143}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 143}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 143}{2 \cdot 1} : 8 + 143

x = \frac{- ( - 16 ) - 2 143}{2 \cdot 1} : 8 - 143

The solutions to the quadratic equation are:

x = 8 + 143, x = 8 - 143

7 x^{2} + 21 x - 28 = 0

2 = 2 x^{2}

x - 6 = - x^{2} - 14 x - 60

H (\frac{1}{2}) = - 5 T^{2} + 10 T

v^{2} - 7 v + 10 = 0

What are the solutions to the equation x^2-16x-84=-5 ?
The solutions to the equation x^2-16x-84=-5 are x=8+sqrt(143),x=8-sqrt(143)
Find the zeros of x^2-16x-84=-5
The zeros of x^2-16x-84=-5 are x=8+sqrt(143),x=8-sqrt(143)