What are the solutions to the equation v^2-7v+10=0 ?

The solutions to the equation v^2-7v+10=0 are v=5,v=2

Find the zeros of v^2-7v+10=0

The zeros of v^2-7v+10=0 are v=5,v=2

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v^{2} - 7 v + 10 = 0

v = 5, v = 2

Solution steps

v^{2} - 7 v + 10 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

v_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, v_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

v = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

v = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

v = 5, v = 2

7 x^{2} + 2 = 0

12 x^{2} + 24 x + 9 = 0

(m + 1) (m + 2) = 0

x^{2} + 2 x - 3 = 0

x, x^{2} + y^{2} + 6 x - 10 y + 34 = 0

What are the solutions to the equation v^2-7v+10=0 ?
The solutions to the equation v^2-7v+10=0 are v=5,v=2
Find the zeros of v^2-7v+10=0
The zeros of v^2-7v+10=0 are v=5,v=2