What are the solutions to the equation 12x^2+24x+9=0 ?

The solutions to the equation 12x^2+24x+9=0 are x=-1/2 ,x=-3/2

Find the zeros of 12x^2+24x+9=0

The zeros of 12x^2+24x+9=0 are x=-1/2 ,x=-3/2

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12 x^{2} + 24 x + 9 = 0

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 0.5, x = - 1.5

Solution steps

12 x^{2} + 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 12 \cdot 9}{2 \cdot 12}

2 4^{2} - 4 \cdot 12 \cdot 9 = 12

x_{1, 2} = \frac{- 24 \pm 12}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 24 + 12}{2 \cdot 12}, x_{2} = \frac{- 24 - 12}{2 \cdot 12}

x = \frac{- 24 + 12}{2 \cdot 12} : - \frac{1}{2}

x = \frac{- 24 - 12}{2 \cdot 12} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{3}{2}

(m + 1) (m + 2) = 0

x^{2} + 2 x - 3 = 0

x, x^{2} + y^{2} + 6 x - 10 y + 34 = 0

5 x^{2} = 11

9 x^{2} + 9 = 450

What are the solutions to the equation 12x^2+24x+9=0 ?
The solutions to the equation 12x^2+24x+9=0 are x=-1/2 ,x=-3/2
Find the zeros of 12x^2+24x+9=0
The zeros of 12x^2+24x+9=0 are x=-1/2 ,x=-3/2