What are the solutions to the equation solvefor x,x^2-y^2=x+y ?

The solutions to the equation solvefor x,x^2-y^2=x+y are x=-y,x=y+1

Find the zeros of solvefor x,x^2-y^2=x+y

The zeros of solvefor x,x^2-y^2=x+y are x=-y,x=y+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} - y^{2} = x + y

x = - y, x = y + 1

Solution steps

x^{2} - y^{2} = x + y

Move

y

to the left side

x^{2} - y^{2} - y = x

Move

x

to the left side

x^{2} - y^{2} - y - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - y^{2} - y = 0

Factor

x^{2} - x - y^{2} - y : (x + y) (x - y - 1)

(x + y) (x - y - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + y = 0 or x - y - 1 = 0

Solve

x + y = 0 : x = - y

Solve

x - y - 1 = 0 : x = y + 1

The solutions to the quadratic equation are:

x = - y, x = y + 1

28 x^{2} = 0

x, y = x^{2} + x

x^{2} - 7 x + 15 = 5

6 (x + 3)^{2} + 20 = 12

2 (x - 5)^{2} + 50 = 0

What are the solutions to the equation solvefor x,x^2-y^2=x+y ?
The solutions to the equation solvefor x,x^2-y^2=x+y are x=-y,x=y+1
Find the zeros of solvefor x,x^2-y^2=x+y
The zeros of solvefor x,x^2-y^2=x+y are x=-y,x=y+1