What are the solutions to the equation 2(x-5)^2+50=0 ?

The solutions to the equation 2(x-5)^2+50=0 are x=5i+5,x=-5i+5

Find the zeros of 2(x-5)^2+50=0

The zeros of 2(x-5)^2+50=0 are x=5i+5,x=-5i+5

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2 (x - 5)^{2} + 50 = 0

x = 5 i + 5, x = - 5 i + 5

Solution steps

2 (x - 5)^{2} + 50 = 0

Move

50

to the right side

2 (x - 5)^{2} = - 50

Divide both sides by

2

(x - 5)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 25 : x = 5 i + 5

Solve

x - 5 = - - 25 : x = - 5 i + 5

The solutions to the quadratic equation are:

x = 5 i + 5, x = - 5 i + 5

5 x^{2} - 6 = 29

(4 + y) (5 y + 8) = 0

12 + 2.4 x - 3 x^{2} = 0

\frac{1}{3} x^{2} + \frac{1}{3} x - \frac{2}{3} = 0

- 3 x^{2} + 12 x + 8 = 0

What are the solutions to the equation 2(x-5)^2+50=0 ?
The solutions to the equation 2(x-5)^2+50=0 are x=5i+5,x=-5i+5
Find the zeros of 2(x-5)^2+50=0
The zeros of 2(x-5)^2+50=0 are x=5i+5,x=-5i+5