What are the solutions to the equation 1/3 x^2+1/3 x-2/3 =0 ?

The solutions to the equation 1/3 x^2+1/3 x-2/3 =0 are x=1,x=-2

Find the zeros of 1/3 x^2+1/3 x-2/3 =0

The zeros of 1/3 x^2+1/3 x-2/3 =0 are x=1,x=-2

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\frac{1}{3} x^{2} + \frac{1}{3} x - \frac{2}{3} = 0

x = 1, x = - 2

Solution steps

\frac{1}{3} x^{2} + \frac{1}{3} x - \frac{2}{3} = 0

Multiply both sides by

3

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

- 3 x^{2} + 12 x + 8 = 0

x^{2} - 4 x + 14 = 13

3 x^{2} - 2 x + 18 = 0

2 x^{2} + 7 x - 13 = - 10

24 = 4 + 37 t - 16 t^{2}

What are the solutions to the equation 1/3 x^2+1/3 x-2/3 =0 ?
The solutions to the equation 1/3 x^2+1/3 x-2/3 =0 are x=1,x=-2
Find the zeros of 1/3 x^2+1/3 x-2/3 =0
The zeros of 1/3 x^2+1/3 x-2/3 =0 are x=1,x=-2