What are the solutions to the equation 3x^2-2x+18=0 ?

The solutions to the equation 3x^2-2x+18=0 are x= 1/3+i(sqrt(53))/3 ,x= 1/3-i(sqrt(53))/3

Find the zeros of 3x^2-2x+18=0

The zeros of 3x^2-2x+18=0 are x= 1/3+i(sqrt(53))/3 ,x= 1/3-i(sqrt(53))/3

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3 x^{2} - 2 x + 18 = 0

x = \frac{1}{3} + i \frac{53}{3}, x = \frac{1}{3} - i \frac{53}{3}

Solution steps

3 x^{2} - 2 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 18 : 253 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 53 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 53 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 53 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 53 i}{2 \cdot 3} : \frac{1}{3} + i \frac{53}{3}

x = \frac{- ( - 2 ) - 2 53 i}{2 \cdot 3} : \frac{1}{3} - i \frac{53}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{53}{3}, x = \frac{1}{3} - i \frac{53}{3}

2 x^{2} + 7 x - 13 = - 10

24 = 4 + 37 t - 16 t^{2}

x, 4 x^{2} y + 2 y^{3} = 1 + 6 x y^{2}

k^{2} + k = 0

x, (x - 2)^{2} + (y + 4)^{2} = 0

What are the solutions to the equation 3x^2-2x+18=0 ?
The solutions to the equation 3x^2-2x+18=0 are x= 1/3+i(sqrt(53))/3 ,x= 1/3-i(sqrt(53))/3
Find the zeros of 3x^2-2x+18=0
The zeros of 3x^2-2x+18=0 are x= 1/3+i(sqrt(53))/3 ,x= 1/3-i(sqrt(53))/3