What are the solutions to the equation 24=4+37t-16t^2 ?

The solutions to the equation 24=4+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)

Find the zeros of 24=4+37t-16t^2

The zeros of 24=4+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)

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24 = 4 + 37 t - 16 t^{2}

t = \frac{37 - 89}{32}, t = \frac{37 + 89}{32}

Decimal Notation

t = 0.86143 \dots, t = 1.45106 \dots

Solution steps

24 = 4 + 37 t - 16 t^{2}

Switch sides

4 + 37 t - 16 t^{2} = 24

Move

24

to the left side

- 16 t^{2} + 37 t - 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 37 \pm 3 7 ^{2} - 4 ( - 16 ) ( - 20 )}{2 ( - 16 )}

3 7^{2} - 4 (- 16) (- 20) = 89

t_{1, 2} = \frac{- 37 \pm 89}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 37 + 89}{2 ( - 16 )}, t_{2} = \frac{- 37 - 89}{2 ( - 16 )}

t = \frac{- 37 + 89}{2 ( - 16 )} : \frac{37 - 89}{32}

t = \frac{- 37 - 89}{2 ( - 16 )} : \frac{37 + 89}{32}

The solutions to the quadratic equation are:

t = \frac{37 - 89}{32}, t = \frac{37 + 89}{32}

x, 4 x^{2} y + 2 y^{3} = 1 + 6 x y^{2}

k^{2} + k = 0

x, (x - 2)^{2} + (y + 4)^{2} = 0

27 = x^{2}

- x^{2} - 3 x + 7

What are the solutions to the equation 24=4+37t-16t^2 ?
The solutions to the equation 24=4+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)
Find the zeros of 24=4+37t-16t^2
The zeros of 24=4+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)