What are the solutions to the equation -x^2+3=x^2+1 ?

The solutions to the equation -x^2+3=x^2+1 are x=1,x=-1

Find the zeros of -x^2+3=x^2+1

The zeros of -x^2+3=x^2+1 are x=1,x=-1

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- x^{2} + 3 = x^{2} + 1

x = 1, x = - 1

Solution steps

- x^{2} + 3 = x^{2} + 1

Move

3

to the right side

- x^{2} = x^{2} - 2

Move

x^{2}

to the left side

- 2 x^{2} = - 2

Divide both sides by

- 2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

16 x^{2} + 9 x - 12 = 4 x + 9 x^{2}

2 x^{2} + 2 x = 24

x, x^{2} y^{2} - 18 x = 3

- 16 t^{2} + 160 t + 120 = 0

5 + 18 x = 35 x^{2}

What are the solutions to the equation -x^2+3=x^2+1 ?
The solutions to the equation -x^2+3=x^2+1 are x=1,x=-1
Find the zeros of -x^2+3=x^2+1
The zeros of -x^2+3=x^2+1 are x=1,x=-1