What are the solutions to the equation x^2-16x+17=0 ?

The solutions to the equation x^2-16x+17=0 are x=8+sqrt(47),x=8-sqrt(47)

Find the zeros of x^2-16x+17=0

The zeros of x^2-16x+17=0 are x=8+sqrt(47),x=8-sqrt(47)

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x^{2} - 16 x + 17 = 0

x = 8 + 47, x = 8 - 47

Decimal Notation

x = 14.85565 \dots, x = 1.14434 \dots

Solution steps

x^{2} - 16 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 17 = 247

x_{1, 2} = \frac{- ( - 16 ) \pm 2 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 47}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 47}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 47}{2 \cdot 1} : 8 + 47

x = \frac{- ( - 16 ) - 2 47}{2 \cdot 1} : 8 - 47

The solutions to the quadratic equation are:

x = 8 + 47, x = 8 - 47

x^{2} + 5 x - 21 = 0

x, 2088.4 x^{2} - 15070 x + 5697.2 = 0

(x - 3)^{2} = - 8 (x + 1)

2 x^{2} - 6 x - 5 = 0

2 x^{2} + 9 x - 7 = 0

What are the solutions to the equation x^2-16x+17=0 ?
The solutions to the equation x^2-16x+17=0 are x=8+sqrt(47),x=8-sqrt(47)
Find the zeros of x^2-16x+17=0
The zeros of x^2-16x+17=0 are x=8+sqrt(47),x=8-sqrt(47)