What are the solutions to the equation x^2-8x=-6x-6x ?

The solutions to the equation x^2-8x=-6x-6x are x=0,x=-4

Find the zeros of x^2-8x=-6x-6x

The zeros of x^2-8x=-6x-6x are x=0,x=-4

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x^{2} - 8 x = - 6 x - 6 x

x = 0, x = - 4

Solution steps

x^{2} - 8 x = - 6 x - 6 x

Refine

x^{2} - 8 x = - 12 x

Move

12 x

to the left side

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

\frac{9}{4} x^{2} - 16 = 0

0.2 x^{2} - 0.9 x + 1 = 0

x^{2} + x + 42 = 0

(7 x + 5)^{2} = 48

6 x^{2} - 208 x + 1280 = 0

What are the solutions to the equation x^2-8x=-6x-6x ?
The solutions to the equation x^2-8x=-6x-6x are x=0,x=-4
Find the zeros of x^2-8x=-6x-6x
The zeros of x^2-8x=-6x-6x are x=0,x=-4