What are the solutions to the equation -3x^2+6x-9=0 ?

The solutions to the equation -3x^2+6x-9=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

Find the zeros of -3x^2+6x-9=0

The zeros of -3x^2+6x-9=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

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- 3 x^{2} + 6 x - 9 = 0

x = 1 - 2 i, x = 1 + 2 i

Solution steps

- 3 x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 9 )}{2 ( - 3 )}

Simplify

6^{2} - 4 (- 3) (- 9) : 62 i

x_{1, 2} = \frac{- 6 \pm 6 2 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 2 i}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 2 i}{2 ( - 3 )}

x = \frac{- 6 + 6 2 i}{2 ( - 3 )} : 1 - 2 i

x = \frac{- 6 - 6 2 i}{2 ( - 3 )} : 1 + 2 i

The solutions to the quadratic equation are:

x = 1 - 2 i, x = 1 + 2 i

x, \frac{x ^{2}}{2} + \frac{z ^{2}}{3} = y

t, x^{2} p^{2} - 2 t x p + 2 x^{2} - t^{2} = 0

x, ln (y) = x^{2}

9 x^{2} + 18 x + 79 = 0

3 m^{2} + 16 m + 21 = 0

What are the solutions to the equation -3x^2+6x-9=0 ?
The solutions to the equation -3x^2+6x-9=0 are x=1-sqrt(2)i,x=1+sqrt(2)i
Find the zeros of -3x^2+6x-9=0
The zeros of -3x^2+6x-9=0 are x=1-sqrt(2)i,x=1+sqrt(2)i