What are the solutions to the equation -4x^2+16=340 ?

The solutions to the equation -4x^2+16=340 are x=9i,x=-9i

Find the zeros of -4x^2+16=340

The zeros of -4x^2+16=340 are x=9i,x=-9i

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- 4 x^{2} + 16 = 340

x = 9 i, x = - 9 i

Solution steps

- 4 x^{2} + 16 = 340

Move

16

to the right side

- 4 x^{2} = 324

Divide both sides by

- 4

x^{2} = - 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 81, x = - - 81

- 81 = 9 i

- - 81 = - 9 i

x = 9 i, x = - 9 i

x^{2} + 8 x - 30 = 0

7 x^{2} = 4

25 x^{2} - 10 x - 15 = 0

3 x^{2} + 5 x + 1

x^{2} + 6^{2} = 9^{2}

What are the solutions to the equation -4x^2+16=340 ?
The solutions to the equation -4x^2+16=340 are x=9i,x=-9i
Find the zeros of -4x^2+16=340
The zeros of -4x^2+16=340 are x=9i,x=-9i