What are the solutions to the equation 7x^2=4 ?

The solutions to the equation 7x^2=4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))

Find the zeros of 7x^2=4

The zeros of 7x^2=4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))

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7 x^{2} = 4

x = \frac{2}{7}, x = - \frac{2}{7}

Decimal Notation

x = 0.75592 \dots, x = - 0.75592 \dots

Solution steps

7 x^{2} = 4

Divide both sides by

7

x^{2} = \frac{4}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{7}, x = - \frac{4}{7}

\frac{4}{7} = \frac{2}{7}

- \frac{4}{7} = - \frac{2}{7}

x = \frac{2}{7}, x = - \frac{2}{7}

25 x^{2} - 10 x - 15 = 0

3 x^{2} + 5 x + 1

x^{2} + 6^{2} = 9^{2}

2 x^{2} + 5 x = 5 x + 50

- 6 + 7 x + 3 x^{2} = 0

What are the solutions to the equation 7x^2=4 ?
The solutions to the equation 7x^2=4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))
Find the zeros of 7x^2=4
The zeros of 7x^2=4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))