What are the solutions to the equation -6+7x+3x^2=0 ?

The solutions to the equation -6+7x+3x^2=0 are x= 2/3 ,x=-3

Find the zeros of -6+7x+3x^2=0

The zeros of -6+7x+3x^2=0 are x= 2/3 ,x=-3

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- 6 + 7 x + 3 x^{2} = 0

x = \frac{2}{3}, x = - 3

Decimal Notation

x = 0.66666 \dots, x = - 3

Solution steps

- 6 + 7 x + 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 3}, x_{2} = \frac{- 7 - 11}{2 \cdot 3}

x = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

10 x^{2} - 3 x + 1

(2 x + 7)^{2} = 48

2 x^{2} - 15 x - 27 = 0

x, y = 5 x - x^{2}

x, x^{2} + 9 x + 20 = 0

What are the solutions to the equation -6+7x+3x^2=0 ?
The solutions to the equation -6+7x+3x^2=0 are x= 2/3 ,x=-3
Find the zeros of -6+7x+3x^2=0
The zeros of -6+7x+3x^2=0 are x= 2/3 ,x=-3