What are the solutions to the equation (2x+7)^2=48 ?

The solutions to the equation (2x+7)^2=48 are x=(4sqrt(3)-7)/2 ,x=(-4sqrt(3)-7)/2

Find the zeros of (2x+7)^2=48

The zeros of (2x+7)^2=48 are x=(4sqrt(3)-7)/2 ,x=(-4sqrt(3)-7)/2

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(2 x + 7)^{2} = 48

x = \frac{4 3 - 7}{2}, x = \frac{- 4 3 - 7}{2}

Decimal Notation

x = - 0.03589 \dots, x = - 6.96410 \dots

Solution steps

(2 x + 7)^{2} = 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 7 = 48 : x = \frac{4 3 - 7}{2}

Solve

2 x + 7 = - 48 : x = \frac{- 4 3 - 7}{2}

The solutions to the quadratic equation are:

x = \frac{4 3 - 7}{2}, x = \frac{- 4 3 - 7}{2}

2 x^{2} - 15 x - 27 = 0

x, y = 5 x - x^{2}

x, x^{2} + 9 x + 20 = 0

9 x^{2} = 2 x

(x - 2) (x + 9) = 42

What are the solutions to the equation (2x+7)^2=48 ?
The solutions to the equation (2x+7)^2=48 are x=(4sqrt(3)-7)/2 ,x=(-4sqrt(3)-7)/2
Find the zeros of (2x+7)^2=48
The zeros of (2x+7)^2=48 are x=(4sqrt(3)-7)/2 ,x=(-4sqrt(3)-7)/2