What are the solutions to the equation solvefor x,x^2+9x+20=0 ?

The solutions to the equation solvefor x,x^2+9x+20=0 are x=-4,x=-5

Find the zeros of solvefor x,x^2+9x+20=0

The zeros of solvefor x,x^2+9x+20=0 are x=-4,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} + 9 x + 20 = 0

x = - 4, x = - 5

Solution steps

x^{2} + 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 1}, x_{2} = \frac{- 9 - 1}{2 \cdot 1}

x = \frac{- 9 + 1}{2 \cdot 1} : - 4

x = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

9 x^{2} = 2 x

(x - 2) (x + 9) = 42

2 k^{2} + 11 k + 14 = 0

y, x^{3} + y^{2} = 4 + x y

24 x^{2} - 48 x = 0

What are the solutions to the equation solvefor x,x^2+9x+20=0 ?
The solutions to the equation solvefor x,x^2+9x+20=0 are x=-4,x=-5
Find the zeros of solvefor x,x^2+9x+20=0
The zeros of solvefor x,x^2+9x+20=0 are x=-4,x=-5