What are the solutions to the equation 2k^2+11k+14=0 ?

The solutions to the equation 2k^2+11k+14=0 are k=-2,k=-7/2

Find the zeros of 2k^2+11k+14=0

The zeros of 2k^2+11k+14=0 are k=-2,k=-7/2

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2 k^{2} + 11 k + 14 = 0

k = - 2, k = - \frac{7}{2}

Decimal Notation

k = - 2, k = - 3.5

Solution steps

2 k^{2} + 11 k + 14 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 14 = 3

k_{1, 2} = \frac{- 11 \pm 3}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 11 + 3}{2 \cdot 2}, k_{2} = \frac{- 11 - 3}{2 \cdot 2}

k = \frac{- 11 + 3}{2 \cdot 2} : - 2

k = \frac{- 11 - 3}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

k = - 2, k = - \frac{7}{2}

y, x^{3} + y^{2} = 4 + x y

24 x^{2} - 48 x = 0

s^{2} - s - 1

x^{2} = 5 + x

12 x^{2} = 9 x

What are the solutions to the equation 2k^2+11k+14=0 ?
The solutions to the equation 2k^2+11k+14=0 are k=-2,k=-7/2
Find the zeros of 2k^2+11k+14=0
The zeros of 2k^2+11k+14=0 are k=-2,k=-7/2