What are the solutions to the equation factor 35n^2+22n+3=0 ?

The solutions to the equation factor 35n^2+22n+3=0 are n=-1/5 ,n=-3/7

Find the zeros of factor 35n^2+22n+3=0

The zeros of factor 35n^2+22n+3=0 are n=-1/5 ,n=-3/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

35 n^{2} + 22 n + 3 = 0

n = - \frac{1}{5}, n = - \frac{3}{7}

Decimal Notation

n = - 0.2, n = - 0.42857 \dots

Solution steps

35 n^{2} + 22 n + 3 = 0

Factor

35 n^{2} + 22 n + 3 : (5 n + 1) (7 n + 3)

(5 n + 1) (7 n + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 n + 1 = 0 or 7 n + 3 = 0

Solve

5 n + 1 = 0 : n = - \frac{1}{5}

Solve

7 n + 3 = 0 : n = - \frac{3}{7}

The solutions to the quadratic equation are:

n = - \frac{1}{5}, n = - \frac{3}{7}

3 x^{2} + 75 = 150

6 x^{2} - 8 x = 64

(x + 1)^{2} + (x + 1) - 12 = 0

- 3 x^{2} + 21 x - 36 = 0

α, x^{2} + α^{2} y^{2} = 4 α^{2}

What are the solutions to the equation factor 35n^2+22n+3=0 ?
The solutions to the equation factor 35n^2+22n+3=0 are n=-1/5 ,n=-3/7
Find the zeros of factor 35n^2+22n+3=0
The zeros of factor 35n^2+22n+3=0 are n=-1/5 ,n=-3/7