What are the solutions to the equation p^2+7p+6=0 ?

The solutions to the equation p^2+7p+6=0 are p=-1,p=-6

Find the zeros of p^2+7p+6=0

The zeros of p^2+7p+6=0 are p=-1,p=-6

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p^{2} + 7 p + 6 = 0

p = - 1, p = - 6

Solution steps

p^{2} + 7 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

p_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 7 + 5}{2 \cdot 1}, p_{2} = \frac{- 7 - 5}{2 \cdot 1}

p = \frac{- 7 + 5}{2 \cdot 1} : - 1

p = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

p = - 1, p = - 6

x^{2} - 18 x - 16 = - 1

8 x^{2} - 3 x + 1 = 0

r, v = n r^{2} h

m^{2} + 36 = 0

x^{2} = 1.5

What are the solutions to the equation p^2+7p+6=0 ?
The solutions to the equation p^2+7p+6=0 are p=-1,p=-6
Find the zeros of p^2+7p+6=0
The zeros of p^2+7p+6=0 are p=-1,p=-6