What are the solutions to the equation 5x^2-25x+3=0 ?

The solutions to the equation 5x^2-25x+3=0 are x=(25+sqrt(565))/(10),x=(25-sqrt(565))/(10)

Find the zeros of 5x^2-25x+3=0

The zeros of 5x^2-25x+3=0 are x=(25+sqrt(565))/(10),x=(25-sqrt(565))/(10)

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5 x^{2} - 25 x + 3 = 0

x = \frac{25 + 565}{10}, x = \frac{25 - 565}{10}

Decimal Notation

x = 4.87697 \dots, x = 0.12302 \dots

Solution steps

5 x^{2} - 25 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

(- 25)^{2} - 4 \cdot 5 \cdot 3 = 565

x_{1, 2} = \frac{- ( - 25 ) \pm 565}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 565}{2 \cdot 5}, x_{2} = \frac{- ( - 25 ) - 565}{2 \cdot 5}

x = \frac{- ( - 25 ) + 565}{2 \cdot 5} : \frac{25 + 565}{10}

x = \frac{- ( - 25 ) - 565}{2 \cdot 5} : \frac{25 - 565}{10}

The solutions to the quadratic equation are:

x = \frac{25 + 565}{10}, x = \frac{25 - 565}{10}

n^{2} - n - 240 = 0

z^{2} + 14 z + 45 = 0

x^{2} - 2 x

x, x^{2} + 7 x - 18 = 0

2 x^{2} - x - 55 = 0

What are the solutions to the equation 5x^2-25x+3=0 ?
The solutions to the equation 5x^2-25x+3=0 are x=(25+sqrt(565))/(10),x=(25-sqrt(565))/(10)
Find the zeros of 5x^2-25x+3=0
The zeros of 5x^2-25x+3=0 are x=(25+sqrt(565))/(10),x=(25-sqrt(565))/(10)