What are the solutions to the equation 6r^2-7r-5=0 ?

The solutions to the equation 6r^2-7r-5=0 are r= 5/3 ,r=-1/2

Find the zeros of 6r^2-7r-5=0

The zeros of 6r^2-7r-5=0 are r= 5/3 ,r=-1/2

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6 r^{2} - 7 r - 5 = 0

r = \frac{5}{3}, r = - \frac{1}{2}

Decimal Notation

r = 1.66666 \dots, r = - 0.5

Solution steps

6 r^{2} - 7 r - 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 5) = 13

r_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 6}, r_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 6}

r = \frac{- ( - 7 ) + 13}{2 \cdot 6} : \frac{5}{3}

r = \frac{- ( - 7 ) - 13}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

r = \frac{5}{3}, r = - \frac{1}{2}

u^{2} - 3 u + 112 = 12 u + 56

3 x^{2} - 8 x - 20 = - 9

x + 1 = x (x - 4)

x, x^{2} - 50 y^{2} - 10 x + 25 = 0

x^{2} + 24 x + 132

What are the solutions to the equation 6r^2-7r-5=0 ?
The solutions to the equation 6r^2-7r-5=0 are r= 5/3 ,r=-1/2
Find the zeros of 6r^2-7r-5=0
The zeros of 6r^2-7r-5=0 are r= 5/3 ,r=-1/2